1/(x+8)=1/(x^2+2)

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Solution for 1/(x+8)=1/(x^2+2) equation: 


D( x )

x^2+2 = 0

x+8 = 0

x^2+2 = 0

x^2+2 = 0

1*x^2 = -2 // : 1

x^2 = -2

x+8 = 0

x+8 = 0

x+8 = 0 // - 8

x = -8

x in (-oo:-8) U (-8:+oo)

1/(x+8) = 1/(x^2+2) // - 1/(x^2+2)

1/(x+8)-(1/(x^2+2)) = 0

1/(x+8)-(x^2+2)^-1 = 0

1/(x+8)-1/(x^2+2) = 0

(1*(x^2+2))/((x+8)*(x^2+2))+(-1*(x+8))/((x+8)*(x^2+2)) = 0

1*(x^2+2)-1*(x+8) = 0

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

(x+2)*(x-3) = 0

((x+2)*(x-3))/((x+8)*(x^2+2)) = 0

((x+2)*(x-3))/((x+8)*(x^2+2)) = 0 // * (x+8)*(x^2+2)

(x+2)*(x-3) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -2, 3 }

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